- When the following conditions are given
PERCENTAGE(%) DIVISION
>=60 1st
>=45 & <60 2nd
>=30 & <45 3rd
<30 FAIL
#include<stdio.h>
#include<conio.h>
void main()
{
int math,phy,chem,hin,eng;
float total,percentage;
clrscr();
printf("\nenter marks of maths=");
scanf("%d",&math);
printf("\nenter marks of phy=");
scanf("%d",&phy);
printf("\nenter marks of chem=");
scanf("%d",&chem);
printf("\nenter marks of hindi=");
scanf("%d",&hin);
printf("\nenter marks of english=");
scanf("%d",&eng);
total=math+phy+chem+hin+eng;
printf("\ntotal=%f",total);
percentage=(total*100)/500;
printf("\npercentage=%f",percentage);
if(percentage<30)
{
printf("\n you are fail");
}
else if(percentage>=30&&percentage<45)
{
printf("\n you have secured 3rd division");
}
else if(percentage>=45&&percentage<60)
{
printf("\n you have secured 2nd division");
}
else if(percentage>=60)
{
printf("\n Congrats ! you have secured 1st division");
}
getch();
}
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